Question

The perimeter of a rectangle is 206m. What will be the area if its length is 33m more than its width?​

Answer 1

Answer :-

The area of rectangle is 2244m².

Step-by-step explanation:

To Find :-

• The area of rectangle.

★ Solution

Given that,

• The perimeter of rectangle = 206m
• The length is 33m more that it's width.

Let us assume the length and breadth of rectangle as (x + 33) and (x) respectively.

We know,

Perimeter of rectangle = 2(length + breadth),

First, finding the width of rectangle :-

⇒ 2 (length + breadth) = Perimeter

⇒ 2 (x + 33 + x) = 206

⇒ 2 (2x + 33) = 206

⇒ 2x + 33 = 206/2

⇒ 2x + 33 = 103

⇒ 2x = 103 - 33

⇒ 2x = 70

⇒ x = 70/2

⇒ x = 35

The value of x is 35, ∴ The length and breadth is :-

• Length = (x + 33) = (35 + 33) = 68m
• Breadth = (x) = 33m

Now, According the question,

• The area of rectangle :-

We know,

Area of rectangle = length × breadth,

⇒ 68m × 33m

⇒ 2244m²

Hence,

The area of rectangle is 2244m².