Question

the perimeter of a rectangle is 20cm it's length is 4m more than its breadth ,find the length and breadth​

Answer 1

Answer:

Let the breadth be x

Then, length =x + 4

ATQ,

2(x + x + 4)= 20

2x + 2x + 8 =20

4x + 8=20

4x=12

x=3

Hence breadth=x=3cm

Length=x +4 = 3+4=7

Answer 2

Given:

• Perimeter of rectangle = 20 cm
• Length of rectangle is 4m more than its breadth.

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To find:

• Length and breadth of rectangle?

⠀⠀━━━━━━━━━━━━━━━━━━━━━

☯ Let breadth of Rectangle be "x" m.

Therefore, Length of Rectangle is (x + 4) m.

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$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(1.8,-0.7)(0,4.2){2}{\sf\large (x + 4) m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large x cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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$\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}$

Perimeter of rectangle = 20 cm

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$\dag\;{\underline{\frak{As\;we\;know\;that,}}}$

$\star\;{\boxed{\sf{\purple{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}$

$:\implies\sf 2[(x + 4) + x] = 40$

$:\implies\sf 2x + 2x + 8 =20$

$:\implies\sf 4x+8 = 20$

$:\implies\sf 4x = 20 -8$

$:\implies\sf 4x = 12$

$:\implies\sf x = \cancel{ \dfrac{12}{4}}$

$:\implies{\underline{\boxed{\frak{\pink{x = 3}}}}}\;\bigstar$

Therefore,

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Breadth of Rectangle, x = 3 m

Length of Rectangle, (x+4) = 3+4 =7m