Question

The perimeter of a rectangle is 210 metres
and its length is 15 metres more than
double the width. Find its length and
width.
​

Answer 1

Answer:

Step-by-step explanation:

let us take width as X

length = ( 15 + 2x)

perimeter = 2 ( l + b)

                 =  2 ( 15 + 2x + x)

                 =  2 ( 15 + 3x )

                 =  30 + 6 x

210 - 30 = 6x

180 = 6x

x = 30

length =  15 +  60)

       =   75

width = 30

Answer 2

Step-by-step explanation:

Let let the width of the rectangle be (x)m.

Then the length of the rectangle is equal to (2x+15)m.

A/Q

2(l+b) = 210

2( 2x+15 +x) = 210

2(3x+15) = 210

6x+30 =210

6x = 210 -30

x = 180 /6

x = 30

So , the width of the rectangle = x metre = 30 metre.

And the length of the rectangle = 2x+15 metre = 75 metre

This is your answer .