the perimeter of a rectangle is 218 cm in length is cm 14 find its areas solutions
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Let breadth of rectangle be x,
then perimeter of rectangle = 2(14 +x)
![218 = 2(14 + x) \\ 218 = 28 + 2x \\ 218 - 28 = 2x \\ 198 \div 2 = x \\ 99 = x 218 = 2(14 + x) \\ 218 = 28 + 2x \\ 218 - 28 = 2x \\ 198 \div 2 = x \\ 99 = x](https://tex.z-dn.net/?f=218+%3D+2%2814+%2B+x%29+%5C%5C+218+%3D+28+%2B+2x+%5C%5C+218+-+28+%3D+2x+%5C%5C+198+%5Cdiv+2+%3D+x+%5C%5C+99+%3D+x)
When breadth = 99 cm,
then Area of rectangle = l × b
![99 \times 14 \\ = 1386 \: cm {}^{2} 99 \times 14 \\ = 1386 \: cm {}^{2}](https://tex.z-dn.net/?f=99+%5Ctimes+14+%5C%5C+%3D+1386+%5C%3A+cm+%7B%7D%5E%7B2%7D+)
Hope it helps. Please Mark "BRAINLIEST" if it does.
then perimeter of rectangle = 2(14 +x)
When breadth = 99 cm,
then Area of rectangle = l × b
Hope it helps. Please Mark "BRAINLIEST" if it does.
Answered by
0
Let the breath of rectangle be x.
Perimeter of rectangle = 2(l+b) = 218 cm
Length = 14 cm
Thus,
2(14+x) = 218 cm
28+2 x = 218 cm
2 x = 218-28
2 x = 190 cm
x = 190/2
x = 95 cm
So the breath = 95 cm
Area of rectangle = (L×b)
= (28×95)
= 2660 cm∧2
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