Question

The perimeter of a rectangle is 22 cm. If its breadth is 4 cm, its length is

Answer 1

AnswEr :

◗The perimeter of a rectangle = 22 cm

◗ Breadth of rectangle = 4 cm

◗ Length of rectangle = ?

Let the Length of the rectangle be 'L' cm.

• According to the Question :

↠Perimeter of rectangle = 2(Length + Breadth)

↠22 = 2(L + 4)

↠22 = 2L + 8

↠22 - 8 = 2L

↠14 = 2L

↠14 ÷ 2 = L

↠7 cm = L

∴ Length of the rectangle is 7 cm

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• V E R I F I C A T I O N :

↠22 = 2(L + 4)

↠22 = 2(7 + 4)

↠22 = 2 × 11

↠22 = 22

Hence, Verified !

• Extra Information :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

AnswEr-:

$\mathrm {\bf{Given-:}}$

• The perimeter of a rectangle is 22 cm.

• The Breadth of a rectangle is 4cm.

$\mathrm {\bf{To\:Find-:}}$

• The Length of Rectangle.

$\sf{\bf{ \underline {\dag{ Solution \:of\:Question \:-:}}}}$

• $\underbrace {\mathrm {\bf{ Understanding \:The\:Concept-:}}}$

• We have to find the Length of Rectangle when Perimeter and Breadth is given .

• Now Putting the Given Values [ Perimeter and Breadth] in Formula for Perimeter of Rectangle.

• By this We can get , The Length of Rectangle.

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$\sf{\bf{ \underline {\dag{ Finding \:Length \:of \:Rectangle \:-:}}}}$

As , We know that ,

• $\underline{\boxed{\star{\sf{\red{Perimeter _{(Rectangle)}  \: = \: 2 (Length + Breadth) }}}}}$

$\mathrm {\bf{Here-:}}$

• The perimeter of a rectangle is 22 cm.

• The Breadth of a rectangle is 4cm.

• The Length of Rectangle is ??

Now By Putting known Values in Formula for Perimeter of Rectangle-:

• $\qquad\quad\quad:\implies { \mathrm {2 ( Length + 4) = 22cm }}$

• $\qquad\quad\quad:\implies { \mathrm { Length + 4 = \dfrac{22}{2} }}$

• $\qquad\quad\quad:\implies { \mathrm { Length + 4 = \dfrac{\cancel {22}}{\cancel {2}} }}$

• $\qquad\quad\quad:\implies { \mathrm { Length + 4 = 11 }}$

• $\qquad\quad\quad\underline {\boxed{\pink{ \mathrm { Length = 7 \:cm }}}}$

Hence ,

• $\underline {\mathrm {\star{\pink {The \: Length \:of \: Rectangle \: is\:7 \:cm}}}}$

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Verification ♡ -:

As , We know that ,

• $\underline{\boxed{\star{\sf{\red{Perimeter _{(Rectangle)}  \: = \: 2 (Length + Breadth) }}}}}$

$\mathrm {\bf{Here-:}}$

• The perimeter of a rectangle is 22 cm.

• The Breadth of a rectangle is 4cm.

• The Length of Rectangle is 7 cm

Now By Putting known Values in Formula for Perimeter of Rectangle-:

• $\qquad\quad\quad:\implies { \mathrm {2 ( 7 + 4) = 22cm }}$

• $\qquad\quad\quad:\implies { \mathrm {2 ( 11) = 22cm }}$

• $\qquad\quad\quad:\implies { \mathrm {22 \: cm = 22cm }}$

Therefore,

• $\qquad\quad\quad:\implies { \mathrm {L.H.S = R.H.S }}$

• $\qquad\quad\quad:\implies { \mathrm {Hence ,\:Verified!}}$

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$\large{\boxed{\sf|\:\:{\underline {More\:To\:Know-:}}\:\:|}}$

• Area of Rectangle = Length × Breadth sq.units

• Area of Square = Side × Side sq.units

• Area of Triangle = ½ × Base × Height sq.units

• Area of Parallelogram = Base × Height sq.units

• Area of Rhombus = ½ × Diagonal 1 × Diagonal 2 sq.units.

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