The perimeter of a rectangle is 22cm and it's area is 28cm².find it's length and it's breadth
Answers
Answered by
3
Step-by-step explanation:
P=22 cm. A=L*W The area is 28 cm^2 and it’s dimensions are L*W, or 4*7 The perimeter is given to be 22 cm and the dimensions are 4 by 7, P=2(L+W), P=2(7+4)
P=2(11), P=22. 22 is the given perimeter.
To check A=4*7 which equals 28 cm^2 is the area.
the perimeter is P=2(4+7) which equals 22 cm is the perimeter.
Therefore the dimensions of the rectangle with area 28 and perimeter 22 is L=7 and W=4.
Answered by
0
Answer:
4cm,7cm
Step-by-step explanation:
perimeter = 2(l+b)
22cm = 2(l+b)
l+b = 11
l = 11-b
area = l×b
28cm² = (11-b)×b
28 = 11b-b²
b²-11b+28 = 0
b²-7b-4b+28 = 0
b(b-7)-4(b-7) = 0
(b-4) (b-7) = 0
b=4,7
if b=4cm then l=7cm, if b=7cm then l=4cm
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