Question

The perimeter of a rectangle is 22cm and it's area is 28cm².find it's length and it's breadth

Answer 1

Step-by-step explanation:

P=22 cm. A=L*W The area is 28 cm^2 and it’s dimensions are L*W, or 4*7 The perimeter is given to be 22 cm and the dimensions are 4 by 7, P=2(L+W), P=2(7+4)

P=2(11), P=22. 22 is the given perimeter.

To check A=4*7 which equals 28 cm^2 is the area.

the perimeter is P=2(4+7) which equals 22 cm is the perimeter.

Therefore the dimensions of the rectangle with area 28 and perimeter 22 is L=7 and W=4.

Answer 2

Answer:

4cm,7cm

Step-by-step explanation:

perimeter = 2(l+b)

22cm = 2(l+b)

l+b = 11

l = 11-b

area = l×b

28cm² = (11-b)×b

28 = 11b-b²

b²-11b+28 = 0

b²-7b-4b+28 = 0

b(b-7)-4(b-7) = 0

(b-4) (b-7) = 0

b=4,7

if b=4cm then l=7cm, if b=7cm then l=4cm