the perimeter of a rectangle is 240 CM if its length is decreased by 10% and breadth is increased by 20% we get the same perimeter find the length and breadth of rectangle
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Let the length be x
breadth be y
1) 2(x+y)=240
2) x+y=120
3) y=120-x
4) Now x-10%x=9x/10
5) y+20%y=12y/10
6) 2(9x/10+12y/10)=240
7) 9x+12y=1200
8) Now 9x+12(120-x)=1200..... using 3)
9) 9x+1440-12x=1200
10) -3x=-240
11)x=80
So length is 80cm
Breadth is 40cm
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breadth be y
1) 2(x+y)=240
2) x+y=120
3) y=120-x
4) Now x-10%x=9x/10
5) y+20%y=12y/10
6) 2(9x/10+12y/10)=240
7) 9x+12y=1200
8) Now 9x+12(120-x)=1200..... using 3)
9) 9x+1440-12x=1200
10) -3x=-240
11)x=80
So length is 80cm
Breadth is 40cm
pls mark as brainliest
indresh834:
@karthik151 thanks
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The length of rectangle = 80cm and,
breadth of rectangle =40cm
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