Question

The perimeter of a rectangle is 24c.m and its area is 20sq.c.m. what is length and breadth in second degree equations

Answer 1

RectangleSolve for length

l =10or2

P -Perimeter 24

A -Area 20

Given: Rectangle

Perimeter(P) = 24 cm

Find: Area(A)

Plan: Use the Perimeter formula to find one rectangular dimension, then calculate the area.

24 = 2L + 2W => by subtracting 2W from both sides of the equation.

2L = 24 - 2W Divide both sides of the equation by 2

L = 12 - W

Now Area(A) = L x W = (12 - W) W = 12W - W^2

Double Check: without some more information that’s is as far as you can go. ✅ ✅

Answer: Area(A) = 12W - W^2