Question

The perimeter of a rectangle is 24cm what are the possible combinations of the length and width of the rectangle if the sides are of integral length write down these combinations find the area of the rectangle for each combination which combination gives you the maximum area how much is it

Answer 1

The combination that will give the maximum area is (6,6)

Perimeter of rectangle = 24cm (Given)

Perimeter of a rectangle= 2(l+b)

Therefore,

2( l+b) = 24

(l+b)= 12

Thus, the combinations which can be formed are -

= (1,11),(2,10), (3,9), (4,8), (5,7), (6,6).

Area of rectangle = Length × Breadth

For (1,11) = 1 × 11 = 11

For (2,10) = 2 × 10 =20

For (3,9) = 3 × 9 = 27

For (4,8) = 4 × 8 = 32

For (5,7) = 5 × 7 = 35

For (6,6) = 6 ×  6 = 36

Thus, the combination (6,6) will give the maximum area of rectangle.

Answer 2

Answer:

Here is your answer may this helps you.