Question

The perimeter of a rectangle is 25 units. If we represent the length as I and the breadth as b, then the
linear equation representing the statement is:​

Answer 1

Diagram:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large l cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large b cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Required Answer :-

Perimeter of a rectangle =25units

As we know that in a rectangle

${\boxed{\sf {Perimeter=2 (l+b)}}}$

• Now Substitute the values

${:}\leadsto$$2 (l+b)=25$

${:}\leadsto$$l+b={\dfrac {25}{2}}$

${:}\leadsto$$l+b-{\dfrac {25}{2}}=0$

$\therefore$$\sf {Required \:linear\;equation=(l+b-{\dfrac {25}{2}}=0)}$