Math, asked by kandhadivaishnavi, 11 hours ago

The perimeter of a rectangle is 26 cm. If the breadth of the rectangle
is 8 cm. Find its length?

Answers

Answered by brainly10038
18

\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Question \; :- }}}}}}}

The perimeter of a rectangle is 26 cm. If the breadth of the rectangle is 8 cm. Find its length?

\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Given \; :- }}}}}}}

  • Perimeter (P) of the rectangle = 26 cm

  • Breadth (B) of the rectangle = 8 cm

\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}

  • Length (L) of the rectangle.

\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Solution \; :- }}}}}}}

Let the Length (L) of the rectangle be x

We Know ;

\large\sf Perimeter (P) = 2 \times (Length (L) + Breadth (B))

B T P ;

\large\sf26 = 2 \times (x + 8)

\large\sf =  > 26 = 2 x + 16

\large\sf =  > 26 - 16 = 2 x

\large\sf =  > 10 = 2 x

\large\sf =  >  \cancel\frac{10 ^{5} }{2 ^{1} }  = x

\large\sf =  >  5 = x

\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Answer \; :- }}}}}}}

The Length (L) of the rectangle is 5 cm.

Answered by llBrutalEmpirell
7

Step-by-step explanation:

\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Question \; :- }}}}}}}

The perimeter of a rectangle is 26 cm. If the breadth of the rectangle is 8 cm. Find its length?

\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; Given \; :- }}}}}}}

\sf Perimeter (P) of \:  the  \: rectangle = 26 cm

\sf Breadth (B) of \:  the \:  rectangle = 8 cm

\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; To \: Find \; :- }}}}}}}

\sf Length (L)  \: of  \: the \:  rectangle.

\large{\underline{\underline{\maltese{\red{\pmb{\sf{ \; Solution \; :- }}}}}}}

\sf Let \:  the \: Length \:  (L) \:  of \:  the \:  rectangle  \: be  \: x

We Know ;

\large\sf Perimeter (P) = 2 \times (Length (L) + Breadth (B))Perimeter(P)=2×(Length(L)+Breadth(B))

B T P ;

\large\sf26 = 2 \times (x + 8)26=2×(x+8)

\large\sf = > 26 = 2 x + 16=>26=2x+16

\large\sf = > 26 - 16 = 2 x=>26−16=2x

\large\sf = > 10 = 2 x=>10=2x

\large\sf = > \cancel\frac{10 ^{5} }{2 ^{1} } = x=>

\pink\large\sf = > 5 = x=>5=x

\large{\underline{\underline{\maltese{\red{\pmb{\sf{ \;Final \:  Answer \; :- }}}}}}}

\fbox\red{The Length (L) of the rectangle is 5 cm}.

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