the perimeter of a rectangle is 260 and its breadth is 60 M find its length and area
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Answered by
3
Perimeter =260
B=60
260=2(l+b)
130=l+b
L=130-b=130-60=70m
So the length is 70m
Hope it helps you
B=60
260=2(l+b)
130=l+b
L=130-b=130-60=70m
So the length is 70m
Hope it helps you
Answered by
0
let the length be x
perimeter of rectangle = 2(l+b)
here, perimeter = 2(50+x)
260/2 =(50+x)'
130=50+x
130-50=x
70=x
then the breadth of rectangle is 60m and length of rectangle is 70
area of rectangle = length *breadth
here , area of rectangle = 70*60
area of rectangle = 4200m^2
perimeter of rectangle = 2(l+b)
here, perimeter = 2(50+x)
260/2 =(50+x)'
130=50+x
130-50=x
70=x
then the breadth of rectangle is 60m and length of rectangle is 70
area of rectangle = length *breadth
here , area of rectangle = 70*60
area of rectangle = 4200m^2
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