the perimeter of a rectangle is 28m.whereas its area is 48m^2 what is the length of its diagonal
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2(l+b)=28
l+b=14---------(1)
lb=48
b=48/l
now put value of b in eq. 1st
l+48/l=14
solve it by quadratic
so =l=6 and l= 8
if we put l=6
then b= 48/6
b=8
if we put l=8
then b=48/8
b=6
so, diagonal= √l^2+b^2
diagonal=√(6)^2+(8)^2
=√36+64
=√100
=10m
l+b=14---------(1)
lb=48
b=48/l
now put value of b in eq. 1st
l+48/l=14
solve it by quadratic
so =l=6 and l= 8
if we put l=6
then b= 48/6
b=8
if we put l=8
then b=48/8
b=6
so, diagonal= √l^2+b^2
diagonal=√(6)^2+(8)^2
=√36+64
=√100
=10m
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