The perimeter of a rectangle is 30 cm and its area is 50cm² find its length and breadth
Answers
Answered by
0
suppose rectangle length x cm & Width is y cm
perimeter of rectangle= 2(x+y)
30 cm= 2(x+y)
x+y= 15 cm
area of rectangle= xy
50cm²=xy
x= 50/y
50/y+y= 15
y²-15y+50= 0
(y-10)(y-5)=0
y=10cm; so x=5cm or y=5cm; so x=10cm
perimeter of rectangle= 2(x+y)
30 cm= 2(x+y)
x+y= 15 cm
area of rectangle= xy
50cm²=xy
x= 50/y
50/y+y= 15
y²-15y+50= 0
(y-10)(y-5)=0
y=10cm; so x=5cm or y=5cm; so x=10cm
Answered by
0
We know that the area is l× b= 50
And the perimeter = 2 ( l+b)= 30
Now l+ b = 30/2
So l+ b = 15
Now we have to find two such numbels whose sum is 15 and product is 50.
Clearly the 2 numberso are 10 and 5
And the perimeter = 2 ( l+b)= 30
Now l+ b = 30/2
So l+ b = 15
Now we have to find two such numbels whose sum is 15 and product is 50.
Clearly the 2 numberso are 10 and 5
Similar questions