Question

The perimeter of a rectangle is 30 m. Its length is 10 m. Its breadth is *
1 point
5 m
10 m
15 m
3 m​

Answer 1

Answer:

The breadth of the given rectangle is 5m. So, option (a) 5m is correct.

Step-by-step explanation:

Given that, the perimeter of a rectangle is 30m and its length is 10m. With this information, we are asked to find the breadth of the rectangle.

We can find the breadth of the given rectangle by using the formula for perimeter of rectangle.

The formula for perimeter of a rectangle is given by,

→ Perimeter of rectangle = 2(l + b)

where, l is the length and b is the breadth of a rectangle in units.

By plugging the given values in the formula, we get the following results:

→ 30 = 2(10 + b)

→ 30/2 = 10 + b

→ 15 = 10 + b

→ 15 - 10 = b

→ 5 = b

Hence, the breadth of the given rectangle is 5m. So, option (a) 5m is correct.

Verification:

Given that, the perimeter of a rectangle is 30m and its length is 10m. And just now we have funded the value of breadth that is 5m.

So on substituting the given values in the formula, we get the following results:

→ 30 = 2(10 + 5)

→ 30 = 2(15)

→ 30 = 30

We can see that, here, both conditions are satisfied. So, we can say that, LHS = RHS.

Hence, verified!

Answer 2

Question :-

• The Perimeter of Rectangle is 30 meter . Its Length is 10 meter . Then, find its Breadth .

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Answer :-

• Breadth of Rectangle is 5 meter .

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Explanation :-

• Here, Perimeter of Rectangle is given 30 m . Length is given 10 m . And, we have to calculate the Breadth .

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➻ Formula Required :-

• $\sf {Perimeter \: of \: Rectangle = 2 \times [ \: L + B \: ]}$

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➻ Where ,

• L denotes to the Length .
• B denotes to the Breadth .

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➻ By substituting the given values :-

$\dag \: \: \sf{ Perimeter \: _{Rectangle} = 2 \times [ \: L + B \: ] }$

$\Longrightarrow \: \: \sf{30 \: = \: 2 \: \times \: [ \: 10 \: \times \: Breadth \: ]}$

$\Longrightarrow \: \: \sf{ \frac{30}{2} \: = \: 10 \: \times \: Breadth }$

$\Longrightarrow \: \: \sf{15 \: = \: 10 \: \times \: Breadth}$

$\Longrightarrow \: \: \sf{Breadth \: = \: 15 \: - \: 10}$

$\Longrightarrow \: \: \sf{Breadth \: = \: 5 \: cm}$

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Hence :-

• Option A [ 5 cm ] is correct .

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Perimeter \: of \: Rectangle = 2 \times (l + b)} \\ \\ \\ \footnotesize \bigstar \: \sf{Perimeter \: of \: Square = 4 \times side} \\ \\ \\ \footnotesize \bigstar \: \sf{Perimeter \: of \: Traingle = a + b + c} \\ \\ \\ \footnotesize \bigstar \: \sf{Perimeter \: of \:Parallelogram = 2 \times (a + b)} \\ \\ \\ \footnotesize \bigstar \: \sf{Perimeter \: of \:Rhombus = 4 \times side} \\ \\ \\ \footnotesize \bigstar \: \sf{Perimeter \: of \:Circle = 2 \pi r} \\ \\ \end{array}}\end{gathered}\end{gathered}$