The perimeter of a rectangle is 30 metres. If it's length exceeds it's breadth by 3 metre, then find its length
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Answered by
0
Answer:
let, the breadth be X and length be X + 3
perimeter = 2( l + b)
30 m = 2 ( x + 3 + x)
15 m = 2x + 3
2x = 12 m
x = 12 / 2 = 6m
breadth = 6m
length = x + 3 = 9 m
Answered by
4
Answer:
p=2(l+b)
let breadth be 'x'
length = x+3
30=2(x+3+x)
=2(2x+3)
30=4x+6
30-6=4x
24=4x
x=6m
breadth is 6m
length is 9m
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