Question

the perimeter of a rectangle is 300 ft, and the length of the rectangle is 3 ft more than twice the width. find the dimentions of the tectangle.

Answer 1

perimeter = 300 ft.
let breadth be x
length = 2× +3
perimeter = 2(l +b)
300 = 2 ( 2× +3 +×)
or 4x +6 +2x = 300
6× =300 - 6
X = 294 ÷6
X = 49
therefore breadth = 49
length = 2X+3 = 2 × 49 +3 = 101