The perimeter of a rectangle is 32 centimeters. The width is 7 centimeters. What is the area of the rectangle?
Answers
Answered by
45
Hello yaar,
Given,
Perimeter of rectangle = 32 cm
Width = 7cm
Perimeter of a rectangle = 2 (l+b)
32cm = 2l + 2 (7cm)
32 cm = 2l + 14cm
32cm -14cm =2l
2l= 18cm
l = 9cm
Area of a rectangle = length × breadth
= 7cm × 9cm
= 63 cm^2
Hope it helps u...
Given,
Perimeter of rectangle = 32 cm
Width = 7cm
Perimeter of a rectangle = 2 (l+b)
32cm = 2l + 2 (7cm)
32 cm = 2l + 14cm
32cm -14cm =2l
2l= 18cm
l = 9cm
Area of a rectangle = length × breadth
= 7cm × 9cm
= 63 cm^2
Hope it helps u...
Answered by
23
perimeter of rectangle= 2(l+b)
we are given width=7cm.
=> 32=2(l+7).
32=2l+14.
32-14=2l.
18=2l.
9=l
now, area of rectangle=lxb.
=9x7=63
area of rect. = 63cm^2.
hope it helps, please mark as brainliest...
we are given width=7cm.
=> 32=2(l+7).
32=2l+14.
32-14=2l.
18=2l.
9=l
now, area of rectangle=lxb.
=9x7=63
area of rect. = 63cm^2.
hope it helps, please mark as brainliest...
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