Question

the perimeter of a rectangle is 32 cm and its length is 10 cm find its breadth​

Answer 1

$\huge{\mathfrak{\green{\star{Answer}}}}$

Perimeter:

$\large{2(l+b)}$

$\large{32cm=2(10cm+b)}$

$\large{32cm/2=10cm+b}$

$\large{16cm=10cm+b}$

$\large{16cm-10cm=b}$

$\large{\implies{6cm=b}}$

Answer 2

Answer:6cm

Step-by-step explanation:

2(l+b)= perimeter

2(10+b)=32

20+2b=32

2b=12

b=6cm