The perimeter of a rectangle is 32 CM the width is 7 centimeters what is the area of the rectangle
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1
Area of the Rectangle=length * Breadth;
we Know the perimeter and width,So by using formula of Perimeter we can Find the Width of the Rectangle
therefore,Perimente=2(l+b);
-------32=2(l+7)j
----------32=2l+14
---------32-14/2=l
---------9cm=l
Now,using Formula of Area of rectangle=9*7;
Therefore,Area of rectangle=63cm Square
we Know the perimeter and width,So by using formula of Perimeter we can Find the Width of the Rectangle
therefore,Perimente=2(l+b);
-------32=2(l+7)j
----------32=2l+14
---------32-14/2=l
---------9cm=l
Now,using Formula of Area of rectangle=9*7;
Therefore,Area of rectangle=63cm Square
Answered by
3
Answer:
Area of the rectangle is 63 cm².
Step-by-step explanation:
Given that ,
Perimeter of the rectangle is 32 cm and the width of the rectangle is 7 cm.
Let,
- Length of the rectangle = x cm
Formula used :
Perimeter of the rectangle = 2(l+b)
According to the question,
2(x+7) = 32
→ x+7 = 32/2
→ x+7 = 16
→ x = 16-7
→ x = 9
Then,
★ Length of the rectangle = 9 cm
Formula used :
Area of the rectangle,
= length× width
= (9×7) cm²
= 63 cm²
Therefore, Area of the rectangle is 63 cm².
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