Question

the perimeter of a rectangle is 32 cm. the width is 7 cm. what is the area of triangle

Answer 1

2(l+b)=32cm

2(l+7)=32cm

length,l=9cm

therefore,area=l×b=63cm

Answer 2

Answer:

Area of the rectangle is 63 cm².

Step-by-step explanation:

Given :-

• The perimeter of a rectangle is 32 cm.
• The width is 7 cm.

To find :-

• The area of the rectangle.

Solution :-

Consider,

• Length of the rectangle = x cm
• Width of the rectangle = 7 cm

Formula used :-

${\boxed{\sf{Perimeter\: of\: rectangle=2(Length+breadth)}}}$

According to the question ,

2(x+7) = 32

→ x+7 = 32/2

→ x +7 = 16

→ x = 16-7

→ x = 9

★ Length = 9 cm

Area of the rectangle ,

= length × Breadth

= 9 × 7 cm²

= 63 cm²

Therefore, the area of the rectangle is 63 cm².