the perimeter of a rectangle is 320 meters its sides are in tha ratio of 5:3 then its area is
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Answered by
7
Let the sides be 5x n 3x
so perimeter will be 2(5x+3x)
ATQ
2(5x+3x) = 320
2*8x = 320
x= 320/16= 20
so the sides r 5* 20= 100 n 3*20= 60
so area = 100*60 m2= 6000m2
hope it helps u.......
☺️
so perimeter will be 2(5x+3x)
ATQ
2(5x+3x) = 320
2*8x = 320
x= 320/16= 20
so the sides r 5* 20= 100 n 3*20= 60
so area = 100*60 m2= 6000m2
hope it helps u.......
☺️
dchawhan009:
Let the common multiple be x
Answered by
11
Hey !! ^_^
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Here is your ans
⬇️⬇️⬇️⬇️⬇️
⏩Let the length and breadth of the de rectangle be 5x and 3x
As per problem
Perimeter = 320
As we know ,
Perimeter of rectangle = 2( length + breadth)
320 = 2( 5x + 3x)
320 = 2 × 8x
8x = 320/2
8x = 160
x = 160/8
x = 20
Length = 5x = 5 × 20 = 100 m
Breadth = 3x = 3 × 20 = 60 m
Area of triangle = length × breadth.
= 60 × 100
= 6,000 m Sq.
_______________________
I HOPE IT WILL HELP YOU ☺️✌️
Thank you ✌️
_____________________
Here is your ans
⬇️⬇️⬇️⬇️⬇️
⏩Let the length and breadth of the de rectangle be 5x and 3x
As per problem
Perimeter = 320
As we know ,
Perimeter of rectangle = 2( length + breadth)
320 = 2( 5x + 3x)
320 = 2 × 8x
8x = 320/2
8x = 160
x = 160/8
x = 20
Length = 5x = 5 × 20 = 100 m
Breadth = 3x = 3 × 20 = 60 m
Area of triangle = length × breadth.
= 60 × 100
= 6,000 m Sq.
_______________________
I HOPE IT WILL HELP YOU ☺️✌️
Thank you ✌️
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