The perimeter of a rectangle is 323232 units. The width is 777 units.
Which equation correctly relates the given information and the length, \ellℓell?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
7 + 32 +7 + 32 = \ell7+32+7+32=ℓ7, plus, 32, plus, 7, plus, 32, equals, ell
(Choice B)
B
7 + \ell +7 + \ell =327+ℓ+7+ℓ=327, plus, ell, plus, 7, plus, ell, equals, 32
(Choice C)
C
7\times\ell=327×ℓ=32
Answers
Answered by
6
Perimeter = length + width + length + width = 2L + 2W
Area = length * width = LW
Given:
W=7
P=32
Substitute values for P and W into first equation:
32 = 2L + 2(7)
32 = 2L + 14
18 = 2L
9 = L
What is A?
A = LW
A = (9)(7)
A = 63 sq-cm
Answered by
0
Answer:
It is 32!
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