Question

The perimeter of a rectangle is 323232 units. The width is 777 units.
Which equation correctly relates the given information and the length, \ellℓell?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
7 + 32 +7 + 32 = \ell7+32+7+32=ℓ7, plus, 32, plus, 7, plus, 32, equals, ell

(Choice B)
B
7 + \ell +7 + \ell =327+ℓ+7+ℓ=327, plus, ell, plus, 7, plus, ell, equals, 32

(Choice C)
C
7\times\ell=327×ℓ=32

Answer 1

Perimeter = length + width + length + width = 2L + 2W

Area = length * width = LW

Given:

W=7

P=32

Substitute values for P and W into first equation:

32 = 2L + 2(7)

32 = 2L + 14

18 = 2L

9 = L

What is A?

A = LW

A = (9)(7)

A = 63 sq-cm

Answer 2

Answer:

It is 32!

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