Question

The perimeter of a rectangle is 348 cm . Find the length of the rectangle if it is two more than three times it's breadth . Please solve this question . ​

Answer 1

ɢɪᴠᴇɴ :-

The perimeter of a rectangle is 348 cm . Find the length of the rectangle if it is two more than three times it's breadth .

ᴛᴏ ғɪɴᴅ :-

• Length (l)
• Breadth (b)

sᴏʟᴜᴛɪᴏɴ :-

Let length of rectangle be x cm and breadth be y cm

then,

✞ According to Question :-

• Length = 3×Breadth + 2

• x = 3y + 2. ---(1)

Now,

➦ Perimeter of Rectangle = 348 cm --(given)

We know that,

➦ Perimeter of Rectangle = 2(l + b)

➭ 2(l + b) = 348

➭ (l + b) = 348/2

➭ l + b = 174

➭ x + y = 174

➭ (3y + 2) + y = 174. --(from-1)

➭ 4y = 174 - 2

➭ 4y = 172

➭ y = 172/4

➭ y = 43

Put y = 43 in (1) , we get,

➭ x = 3y + 2

➭ x = 3×43 + 2

➭ x = 129 + 2

➭ x = 131

Hence,

• Length(l) = x = 131 cm
• Breadth(b) = y = 43 cm

Answer 2

Answer:

Step-by-step explanation:

348=perimeter

Perimeter =2(L+B)

Length is said to be 2 more than 3 times breadth..

so L=2+3B

Put this value in this equation

348=2(L+B)

348=2{(2+3B)+B}

348={4+8B}

348=4+8B

Now transfer 4 to left hand side

348-4=8B

344=8B

344/8=B

Breadth=43 cm

Length was 2 more than 3times breadth

Length=2+3(43)

Length=131 cm