Question

The perimeter of a rectangle is 38 m. If its length is 5 m less than twice its width, find the dimensions of the rectangle.
Ans-11 length & 8 width . Pls tell proper process . Irrelevant answer will be reported.​​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

The perimeter is twice the length plus twice the width, or 2x+2y.

Therefore, 2x+2y = 38 as given.

Also, the length is 5 ft longer than the width so x = y + 5

Knowing these equations are true, you can solve.

Substitute for x: 2(y+5) + 2y = 38

Distribute: 2y + 10 + 2y = 38

Simplify: 4y + 10 = 38

Subtract 10: 4y=28

Divide by 4: y=7

x=y+5 = 12

The length is 12, which is 5 more than the width of 7. The perimeter is 2(12+7) = 2(19) = 38