Question

the perimeter of a rectangle is 40 cm and its area is 96 square cm find the length and breadth of a rectangle​

Answer 1

Let the length of a rectangle = a cm.

breadth of the rectangle = b cm

2(a+b)=40

a+b=20 ----------------> (1)

ab=96 ----------------> (2)

(a-b)^2 = (a+b)2 - 4ab

⇒(a-b)^2 = 20^2 - 4x96

⇒400 - 384 = 16

a-b = 4 ----------------> (3)

On adding eq^n (1) & (3)

2a = 24

⇒a = 24/2

⇒a = 12

put a = 12 in eq^n (1)

12 + b = 20

⇒b = 20 - 12

⇒b = 8 cm

Length = 12 cm, breadth = 8 cm

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OM!