Question

The perimeter of a rectangle is 40 cm. The
length of the rectangle is more than double its
breadth by 2. Find length and breadth.​

Answer 1

Answer:

Length = 14 cm.

Breadth = 6 cm.

Step-by-step explanation:

Given :

The perimeter of a rectangle is 40 cm.

The  length of the rectangle is more than double its  breadth by 2.

To Find :

The length and breadth.​

Solution :

Let the :

Breadth = b cm

Length (l) = 2b+2

Perimeter (P) = 40 cm.

So,

$\sf\\ \\\implies 2(l+b)=40\\ \\ \implies 2(2b+2+b) = 40\\ \\ \implies 2(3b+2)=40$

Now,

Dividing both sides by 2,

$\sf\\ \\\implies 3b+2 = 20\\ \\ \implies 3b = 20-2\\ \\\implies 3b = 18$

If you divide each term by 3,

We get,

⇒ b = 6

Hence,

$\sf\\ \\Breadth (b) = 6 cm\\ \\ Length (l) = 2b+2\\ \\ \implies 2\times6+2\\ \\ \implies 12+2\\\\ \implies 14 cm.$

$\rule{300}{1.5}$

$\setlength{\unitlength}{2cm}\begin{picture}(16,4)\thicklines\put(8,3){\circle*{0.1}}\put(7.8,3){\large{D}}\put(7.2,2){\mathsf{\large{6cm}}}\put(8,1){\circle*{0.1}}\put(7.8,1){\large{A}}\put(9.3,0.8){\mathsf{\large{14cm}}}\put(11.1,1){\large{B}}\put(8,1){\line(1,0){3}}\put(11,1,){\circle*{0.1}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(11,3){\circle*{0.1}}\put(11.1,3){\large{C}}\end{picture}$

$\rule{300}{1.5}$

#AnswerWithQuality.

#BAL! :)

Answer 2

$\huge\underline\mathrm{Question-}$

The perimeter of a rectangle is 40 cm. The length of the rectangle is more than double its breadth by 2. Find length and breadth.

$\huge\underline\mathrm{Solution-}$

Given :

• Perimeter of rectangle = 40 cm

• The length of the rectangle is more than double its breadth by 2.

To find :

• Length of rectangle

• breadth of rectangle

Figure :

$\setlength{\unitlength}{2cm}\begin{picture}(16,4)\thicklines\put(8,3){\circle*{0.1}}\put(7.8,3){\large{D}}\put(7.2,2){\mathsf{\large{?cm}}}\put(8,1){\circle*{0.1}}\put(7.8,1){\large{A}}\put(9.3,0.8){\mathsf{\large{?cm}}}\put(11.1,1){\large{B}}\put(8,1){\line(1,0){3}}\put(11,1,){\circle*{0.1}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(11,3){\circle*{0.1}}\put(11.1,3){\large{C}}\end{picture}$

Explanation :

Let the breadth of rectangle be x.

•°• Length = 2x + 2

Now, by using perimeter of rectangle,

$\large\boxed{\rm{Perimeter\:of\:rectangle=2(L+B)}}$

Putting the values which we supposed,

$\implies$ Perimeter of rectangle = 2[(2x+2)+(x)]

$\implies$ 40 = 2(3x+2)

$\implies$ 40 = 6x + 4

$\implies$ 40 - 4 = 60

$\implies$ x = $\cancel{\dfrac{36}{6}}$

$\rule{200}1$

Breadth of rectangle = x

★ $\large\boxed{\rm{Breadth\:of\:rectangle=6\:cm}}$

Length of rectangle = 2x + 2

$\implies$ 2(6) + 2

$\implies$ 12 + 2

★ $\large\boxed{\rm{Length\:of\:rectangle=14\:cm}}$