The perimeter of a rectangle is 40 m. If its length is 4 m less than breadth, then the area of the rectangle is.
P.S=Tommorow is my final exam and by solving this you are helping me a lot,so thanks in advance may you get goodluck :)
sakshipriyano1:
take breadth x and length X minus 4
did that
hmm
q-3=let breath be x
perimeter=2x(l+b)
40m=2x((4-x)+x)
40m/2=(4-x)+x
20m=(4-x)+x
20-4=-x+x
16m=+x-x
perimeter=2x(l+b)
40m=2x((4-x)+x)
40m/2=(4-x)+x
20m=(4-x)+x
20-4=-x+x
16m=+x-x
till here i have solved
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let the bredth is x
length = 4-x
perimeter = 2(l+b)
40= 2(x+x-4)
40= 2(2x-4)
40/2 = 2x - 4
20+4= 2x
24/2= x
x=12
b=12.
l=12-4
= 8
area of rectangle = lb
= 12×8
= 96m²
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