Question

the perimeter of a rectangle is 40 m. its length is 12 m. find the area of the rectangle​

Answer 1

Given:-

• Perimeter of rectangle = 40m
• Length of rectangle = 12m

To find:-

• Area of rectangle

Solution :-

Let b is consider as breadth of rectangle.

We know that,

Perimeter of rectangle = 2 ( length + breadth )

⇒ 40m = 2 ( 12 + b )

⇒ 40 = 24 + 2b

⇒ 2b = 40 - 24

⇒ 2b = 16

⇒ b = 16/2

⇒ b = 8m

Therefore, breadth of rectangle is 8m.

Now,

Area of rectangle = length × breadth

= 12m × 8m

= 96m²

Hence, area of rectangle is 96m².

Answer 2

Answer:

Given :-

• Perimeter of rectangle = 40 m
• Length of rectangle = 12 m

To Find :-

Area of rectangle

Solution :-

Firstly let's find Breadth of rectangle

As we know that

$\fbox{Perimeter = 2(l + b)}$

$\tt \: 40 = 2(12 + b)$

$\tt \: 40 = 24 + 2b$

$\tt \: 40 - 24 = 2b$

$\tt \: 16 = 2b$

$\tt \: b \: = \dfrac{16}{2}$

$\tt \: b = 8$

Now,

Let's find Area

$\boxed{ \sf \: Area = l \times b}$

$\tt \: Area = 12 \times 8$

$\tt \: Area = 96 \: {m}^{2}$

Hence :-

Area of rectangle is 96 m².