the perimeter of a rectangle is 40 metre the length of the rectangle is 4 m less than 5 times its breadth find the length of a rectangle
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Let the breadth be x.m
the length be 5x- 4m
So perimeter= 2[(5x-4)+x]m
= 2(5x+x-4)
=2(6x-4)
=12x-8
By condition,
12x-8= 40
12x= 40-8
12x= 36
x= 36/12
x= 3
Therefore breadth = 3m
and length =( 5×3)+4m= 15+4m= 19m.
the length be 5x- 4m
So perimeter= 2[(5x-4)+x]m
= 2(5x+x-4)
=2(6x-4)
=12x-8
By condition,
12x-8= 40
12x= 40-8
12x= 36
x= 36/12
x= 3
Therefore breadth = 3m
and length =( 5×3)+4m= 15+4m= 19m.
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