Question

The perimeter of a rectangle is 40 metres. If its length is 4 metres more than its width, find the dimensions of

the rectangle. ( pls give step by step solution )​

Answer 1

Answer:

Perimeter of rectangle = 40.

Length of rectangle = 4 m.

Breadth of rectangle = 2( l + b ) = 40

= 2( 4 + b ) = 40

= 8 + 2b = 40

40 = 8 + 2b

40 - 8 = 2b

32 = 2b

32/2 = b

18 = b

And foollo me.

Answer 2

Answer :

• Width is 8m
• Length = x + 4 = 8 + 4 = 12m

Given :

• Perimeter of a rectangle is 40m
• The length is 4 m more than its width

To find :

• Breadth
• Dimensions of the rectangle

Solution :

As we know that ,

Length is 4m more than its width so ,

• Let the width be x
• Length be (x + 4)m

As we know that,

• Perimeter of rectangle = 2(length + breadth)

Given perimeter is 40m so,

》Perimeter of rectangle = 2(l + b)

》40 = 2(x + 4 + x)

》x + 4 + x = 40/2

》2x + 4 = 20

》2x = 20 - 4

》2x = 16

》x = 16/2

》x = 8m

Hence,

• Width is 8m
• Length = x + 4 = 8 + 4 = 12m
• Dimensions of rectangle are 8m and 12m

More Explanation :

• Perimeter of rectangle = 2(l + b)
• Area of rectangle = length × breadth
• Diagonal = √l² + b²