Math, asked by praveenmaan1978, 10 months ago

the perimeter of a rectangle is 40m.if the sides of the rectangle are natural noumber find the dimensions of the rectangle having the maximum area​

Answers

Answered by vishalyadav610
1

Answer:

Your gut feeling may tell you it's a square, with sides 10 ft, or a total area of 100 sqft.

Explanation:

You can divert from this and see if the area gets any larger, or you can use the mathematical way:

If the length =

x

and the width =

y

then the perimeter

P

=

40

P

=2x+2y

=40→x+y

=20→y

=20−x

As for the area A :A=x⋅y

=x.(20−x)

=20x−x2

And we have to find an extreme for that:

We can do this by setting the derivative to

=0

A

'

=20−2x

=0→x

=10→y

=10

Just as we thought in the first place.

graph{20x-x^2 [-131.6, 135.4, -8.4, 125.1]}

hope it help you

plz mark it

Answered by rockingstar1629
0

Answer:

Your gut feeling may tell you it's a square, with sides 10 ft, or a total area of 100 sqft.

Explanation:

You can divert from this and see if the area gets any larger, or you can use the mathematical way:

If the length =

x

and the width =

y

then the perimeter

P

=

40

P

=2x+2y

=40→x+y

=20→y

=20−x

As for the area A :A=x⋅y

=x.(20−x)

=20x−x2

And we have to find an extreme for that:

We can do this by setting the derivative to

=0

A

'

=20−2x

=0→x

=10→y

=10

Just as we thought in the first place.

graph{20x-x^2 [-131.6, 135.4, -8.4, 125.1]}

hope it help you

Step-by-step explanation:

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