The perimeter of a rectangle is 40m.its length is four meter less than five times it's breadth. Find the area of rectangle
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Step-by-step explanation:
Let, breadth of rectangle is x, then 5x−4 be the length of the rectangle.
Perimeter of rectangle =2(l+b)
⇒40=2(l+b)
⇒40=2(5x−4+x)
⇒40=12x−8
⇒12x=40+8
⇒12x=48
⇒x=
12
48
⇒x=4
Breadth =4 meters
Hence, length =5×4−4=20−4=16m
Therefore, area of rectangle =lb=16×4=64m
2
Answered by
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QUESTION :-
The perimeter of a rectangle is 40m.its length is four meter less than five times it's breadth. Find the area of rectangle .
TO FIND :-
- area of rectangle
HOW TO FIND :-
- we have to consider breadth of that rectangle as x
- as given in question that the length is four meter less than five times it's breadth. so , we have to consider length as 5x - 4 .
- to find the area we have to first find the perimeter that is = 2(l +b).
- from here we get the breadth .
- to find the length we put the value of x in 5x-4.
- then we get both length and breadth so now we will Multiply that a s....
- area of rectangle is = l × b
- now whole solution is done ✅⚡by the process .
SOLUTION :-
Let, breadth of rectangle is x, then 5x−4 be the length of the rectangle.
Perimeter of rectangle =2(l+b)
⇒40=2(l+b)
⇒40=2(5x−4+x)
⇒40=12x−8
⇒12x=40+8
⇒12x=48
⇒x= 12 /48
•°•x=4
Breadth =4 meters
Hence, length =5×4−4=20−4=16m
Therefore, area of rectangle =lb=16×4=64m²
HOPE I EXPLAINED YOU CLEARLY .✅BE BRAINLY ⚡
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