Question

The perimeter of a rectangle is 42 m and its diagonal is 15 m.What are the lengths of its sides?

Answer 1

by using this formula we can find :-

p= 2(l+w)

d= √(w^2+l^2)

there are two solutions for l

l = p/4 +1/4 √8d^2 - p^2

=42/4 +1/4.√8.15^2-42^2 =12m

l= p/4-1/4 √8d^2-p^2

= 42/p - 1/4.√8.15^2-42^2

= 9 m

I hope this will helps you

Answer 2

Answer:

by using this formula we can find

p 2(ltw)

ds V(w 2+1^2)

there are two solutions for I

p/4 +1/4 V8d 2-p^2

42/4 +1/4.v8.15 2-42*2 =12m

F p/4-1/4 v8d 2-p^2

42/p-1/4.v8.15^2-42^2

9 m

I hope this will helps you

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