The perimeter of a rectangle is 42 meters and its diagonals is 15 meters. What are the length of its sides?
Answers
The perimeter of a rectangle is 42 meters and its diagonals is 15 meters. What are the length of its sides?
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formula for diagonal:-
=>Diagonal is given which is 15metres
There are two solutions for finding length:-
hence,the length of the sides is either 9m or 12m
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Given :
- Perimeter of rectangle = 42 m
- Diagonal of rectangle = 15 m
To Find :
- Length = ?
- Breadth = ?
Answer :
➻ Perimeter of reactangle = 2(Length + Breadth)
- Let Length be 'l' and Breadth be 'b'.
➻ 42 = 2(l + b)
➻ 42 ÷ 2 = (l + b)
➻ 21 = (l + b) ........[Equation (i)]
Now,by using Phythagoras theorem we get :
➻ (l)² + (b)² = (15)²
➻ l² + b² = 225 ......[Equation (ii)]
Now, Taking equation (i) :
➻ l + b = 21
Squaring both the sides
➻ (l + b)² = (21)²
➻ l² + b² + 2lb = 441
Replacing l² + b² by 225 from equation (ii) :
➻ 225 + 2lb = 441
➻ 2lb = 441 - 225
➻ 2lb = 216
Dividing both sides by 2 we get :
➻ lb = 108 .......[Equation (iii)
Taking equation (i) again we get :
➻ l + b = 21
➻ l = 21 - b ......[Equation (iv)]
Substituting the value of 'l' from equation (iv) in equation (iii) we get :.
➻ (21 - b) (b) = 108
➻ -b² + 21b = 108
➻ -b² + 21b - 108 = 0
By splitting the middle term we get :
➻ -b² -12b - 9b - 108 = 0
➻ -b(b - 12) + 9(b - 12) = 0
➻ (-b + 9) (b -12)
➻ b = 12 m or b = 9 m
- When b = 12 m then Length will be :
➻ l + b = 21 [from equation (i)]
➻ l + 12 = 21
➻ l = 9 m
- When b = 9 m then Length will be :
➻ l + b = 21 [from equation (i)]
➻ l + 9 = 21
➻ l = 12 m
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