Question

the perimeter of a rectangle is 42cm and its area is 95 sq.cm

find the sides​

Answer 1

Step-by-step explanation:

Let length of rectangle = x cm

And breadth of rectangle = y cm

Given : Perimeter = 42 and area = 95

To find : x and y.

$perimeter \: = 42 \\ 2(x + y) = 42 \\ x + y = 21 \\ y = 21 - x.................(1) \\ \\ area \: = 95 \\ xy = 95 \\ x(21 - x) = 95 \\ 21x - {x}^{2} = 95 \\ {x}^{2} - 21x + 95 = 0 \\ x = \frac{21 + \sqrt{441 - 4 \times 95 \times 1} }{2 \times 1} \\ or \: x = \frac{21 - \sqrt{441 - 4 \times 95 \times 1} }{2 \times 1} \\ x = \frac{21 + \sqrt{61} }{2} \: or \: \frac{21 - \sqrt{61} }{2} \\ x = \frac{21 + 7.8}{2} \: or \: \frac{21 - 7.8}{2} \\ x = 14.4 \: or \: 6.6 \\ so \: y \: = 6.6 \: or \: 14.4$

Answer 2

Answer:

this is correct..........................