The perimeter of a rectangle is 44 cm .if its length is increased by 4 cm and its breadth is increased 2 cm its area is increased by 72 sqcm Find the dimensions of the rectangle.
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Answered by
56
Perimeter = 44
2 (L + b) = 44
L + b = 22
L = 22-b. *****eqn a
(L+4)(b+2)= Lb+72
Lb + 2L + 4b + 8 = Lb+ 72
2L + 4b + 8 = 72
2L + 4b = 72 - 8
2(L + 2b) = 64
L + 2b = 32
Substitute for L
(22-b) + 2b = 32
22 + b = 32
b = 10 cm
L = 22- b
= 22-10
= 12 cm
So:
Length= 12 cm
Breadth= 10cm
2 (L + b) = 44
L + b = 22
L = 22-b. *****eqn a
(L+4)(b+2)= Lb+72
Lb + 2L + 4b + 8 = Lb+ 72
2L + 4b + 8 = 72
2L + 4b = 72 - 8
2(L + 2b) = 64
L + 2b = 32
Substitute for L
(22-b) + 2b = 32
22 + b = 32
b = 10 cm
L = 22- b
= 22-10
= 12 cm
So:
Length= 12 cm
Breadth= 10cm
Answered by
19
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