Question

. The perimeter of a rectangle is 48 cm. If the length is double of its breadth, find
its length, breadth and area.​

Answer 1

Step-by-step explanation:

Let x be the breadth

so length = 2x

now

perimeter of a rectangle = 2(l+b)

=48= 2(2x+x )

=48/2= 3x

=24 =3x

= 24/3 =x

therefore

x = 8 cm

i e. breadth = 8 cm

now length = 2× 8cm

= 16 Cm

now Area = l×b

16 cm × 8 cm

= 128 cm ²

Answer 2

Answer:

Length = 16 cm

Breadth= 8 cm

Area = 128 cm²

Step-by-step explanation:

Given :

Perimeter of the rectangle = 48 cm

Length is double to its breadth

To find :

(i) Length

(ii) Breadth

(iii) Area

Concept :

Let the Length be 2x

Let the Breadth be x

So , to find the length and breadth use this equation -:

$\boxed{\rm{2(L+B)=P}}$

Where,

L = Length

B = Breadth

P = Perimeter

After that to find the area of the rectangle use this formula -:

$\boxed{\rm{A=L\:\times\:B}}$

Where,

A = Area of the rectangle

Solution :

$:\Rightarrow\rm{2(2x+x)=48cm}$

$:\Rightarrow\rm{4x+2x=48cm}$

$:\Rightarrow\rm{6x=48cm}$

$:\Rightarrow\rm{x=\cancel{\dfrac{48cm}{6}}}$

$:\Rightarrow\rm{x=8cm}$

So , the Breadth is 8 cm .

Length -:

Length = 8cm × 2

Length = 16 cm

Area of the rectangle -:

$:\Rightarrow\rm{A=16cm\times8cm}$

$:\Rightarrow\rm{A={128cm}^{2}}$

So , the area of the rectangle is 128 cm² .