Question

The perimeter of a rectangle is 48 cm. What is its area, if the length is twice the breadth ?​

Answer 1

Answer:

Answer in the attachment

Step-by-step explanation:

I hope it helped you Uhh (+_+)

Answer 2

Answer:

$\rm 128\: cm^2$

Step-by-step explanation:

$\rm Let \: length = x$

$\rm Let \: breadth = y$

We know that,

$\boxed{\rm Perimeter_{Rectangle} = 2(l+b)}$

$\rm 48= 2(x+y)$

$\rm x+y= 24$

length is twice the breadth,

$\rm x = 2y$

Put the value of x,

$\rm 2y+y=24$

$\rm 3y=24$

$\rm y=8$

$\rm x = 2y$

$\rm x = 2×8=16$

We know that,

$\boxed{\rm Area_{Rectangle}= length×breadth}$

$\rm Area = x×y$

$\rm =8×16=128\: cm^2$