Question

The perimeter of a rectangle is 48cm. If the sides are in the ratio 3:5, find the lengths of the sides.

Answer 1

Step-by-step explanation:

Perimeter of a rectangle= 2(l+b)

l/b=3/5

5l=3b

l=3b/5

Perimeter=2(3b/5+b)

48=2(5b+3b/5)

48/2=8b/5

23=8b/5

23*5=8b

115=8b

b=115/8

b=14.375

l=3b/5

l= 3(14.375)/5

l= 3(2.475)

l=7.425

Answer 2

☯GIVEN :

• Perimeter of the rectangle = 48 cm

• Sides are in the ratio = 3:5

☯TO FIND :

• The length and breadth of the rectangle.

☯FORMULA REQUIRED :

$\bigstar{\underline{\red{\boxed{ \bf{Perimeter = 2(length + breadth)}}}}}$

➲SOLUTION :

✞Let the length and breadth of the rectangle be 5x cm and 3x cm.

$: \implies {\sf{Perimeter = 48}}$

$: \implies {\sf {2(5x+3x)= 48}}$

$: \implies {\sf {2 \times 8x= 48}}$

$:\implies {\sf {16x= 48}}$

$: \implies {\sf {x= \cancel {\dfrac{48}{16}}}}$

$: \implies \underline{\pink{ \boxed{\bf{x= 3}}}}$

$\huge { \red{\therefore}}$ Length = $\sf {5\times 3}$= $\bf { 15\:cm}$

$\huge { \red{\therefore}}$Breadth =$\sf {3 \times 3}$= $\bf { 9\:cm}$