Math, asked by nramamani, 2 months ago

The perimeter of a rectangle
is 48cm . The length of the rectangle is 3cm more than
twice its breathe . Find the
length and breadth?​

Answers

Answered by sdirector7
8

Answer:

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Answered by shaktisrivastava1234
1074

 \huge \fbox{Answer}

 \large \underline{ \underline{ \frak{ \color{blue}{Given:}}}}

 \mapsto  \sf{Perimeter \:  of  \: rectangle=48cm}

 \mapsto \sf{Breadth \:  of  \: rectangle= { \bf b}cm}

 {\mapsto \sf{Length\:  of  \: rectangle= 2{ \bf b} + 3cm}}

 \large \underline{ \underline{ \frak{ \color{orange}{To \:  find:}}}}

{ \leadsto \sf{Length \:  and  \: Breadth  \: of  \: rectangle. }}

 \large \underline{ \underline{ \frak{ \color{cyan}{Formula \:  required:}}}}

  \dag\underline{ \red{ \boxed{ \blue{\rm{Perimeter \:  of  \: rectangle=2(length + breadth)}}}}}

 \large \underline{ \underline{ \frak{ \color{indigo}{According \:  to  \: Question:}}}}

 \bf \underline{Let's \:  start  \: now!!!}

{  \dashrightarrow \sf{Perimeter \:  of  \: rectangle=2(length + breadth)}}

{  \dashrightarrow \sf{48cm=2(2{ \bf b} + 3+  {\bf b)}}}

{  \dashrightarrow \sf{ \frac{48}{2}  cm= 2{ \bf b} + 3+  {\bf b}}}

{  \dashrightarrow \sf{ \cancel{ \frac{48}{2}}cm= 2{ \bf b} + 3+  {\bf b}}}

{  \dashrightarrow \sf{ 24cm= 2{ \bf b} + 3+  {\bf b}}}

{  \dashrightarrow \sf{ 24cm= 3{ \bf b} + 3 }}

{  \dashrightarrow \sf{3{ \bf b}  = 24cm - 3cm}}

{  \dashrightarrow \sf{3{ \bf b}  = 21cm}}

{  \dashrightarrow \sf{{ \bf b}  =  \frac{21}{3} cm}}

{  \dashrightarrow \sf{{ \bf b}  =   \cancel{\frac{21}{3}} cm}}

{  \dashrightarrow \sf{{ \bf b}  =   7 cm}}

 \bf \underline{Then,}

{ \mapsto \sf{Breadth \:  of  \: rectangle= { \bf b}cm = 7cm}}

 {\mapsto \sf{Length\:  of  \: rectangle= 2{ \bf b} + 3cm = 2 \times 7cm + 3} = 17cm}

 \large \underline{ \underline{ \frak{ \color{black}{ \red{ \checkmark}}{Verification:}}}}

{  \dashrightarrow \sf{Perimeter \:  of  \: rectangle=2(length + breadth)}}

{  \dashrightarrow \sf{48cm=2(17cm+ 7cm)}}

{  \dashrightarrow \sf{48cm=2 \times 24cm}}

{  \dashrightarrow \sf{48cm = 48cm}}

{  \dashrightarrow \sf{L.H.S.=RH.S.}}

 \bf \underline{Hence,}

   \:  \:  \:  \:   \: \star{\underline{ \blue{ \boxed{ \red{\rm{Breadth \:  of  \: rectangle=  7cm}}}}}}

   \:  \:  \:  \:   \: \star{\underline{ \blue{ \boxed{ \red{\rm{Length\:  of  \: rectangle=  17cm}}}}}}

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