Question

The perimeter of a rectangle is 50 cm and its length is 15 cm. Finding breadth

Answer 1

Perimeter of the rectangle =

2( Length + Breadth)

Let the Breadth be b.

A/C :

2( l + b) = 50cm

$= > 2(15 + b) = 50 \\ = > 30 + 2b = 50 \\ = > 2b = 50 - 30 \\ = > b = \frac{20}{2} \\ = > b = 10$

Therefore, The Breadth is 10cm

Answer 2

Answer:

.

The breadth of rectangle= 10 cm

.

Step-by-step explanation:

$length \: of \: a \: rectangle = 15 \: cm \\ \\ let \: breadth \: of \: rectangle = x \: \: cm \\ \\ perimeter \: of \: recangle \: = 50 \: cm \\ \\ 2(length + breadth) = 50 \\ \\ 15 + x = \frac{50}{2} \\ \\ 15 + x = 25 \\ \\ x = 25 - 15 \\ \\ x = 10 \: cm \\ \\ breadth \: of \: rectangle = 10 \: cm \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$