Question

the perimeter of a rectangle is 50 cm .if it breadth is 10 . what is it's length​

Answer 1

Answer:

perimeter of rectangle = 50cm

2(l+b)=50

2(l+10)=50

2l+20 = 50

2l = 30

l = 15 cm is your required answer

Step-by-step explanation:

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Answer 2

Given:-

• Perimeter of a rectangle = 50cm.
• Breadth = 10cm.

To find:-

• Length of a rectangle.

Solution:-

$\bold { \sf{ \red{Perimeter \: of \: a \: rectangle \: = 2(l + b)}}}$

Let the length be 'x'.

$\bold { \sf{ \red{50 \: = 2(x \: + \: 10 )}}}$

$\bold { \sf{ \red{50 \: = 2x \: + \: 20 }}}$

$\bold { \sf{ \red{ - 2x = - 50 + 20}}}$

$\bold { \sf{ \red{ - 2x = - 30}}}$

$\bold{ \sf{ \red{x = \frac{ \cancel{ - 30}}{ \cancel{ - 2}}}} }$

$\bold{ \sf{ \red{x = 15 }}}$