The perimeter of a rectangle is 50 cm.Its length is 32 cm. Find the breadth?
Answers
Answered by
3
Hey!! here is your answer......
perimeter of rectangle =2(l+b)
Given=length =32cm
perimeter=50
let breadth =b
perimeter =2(l+b)
50=2(32+b)
50÷2=32+b
25=32+b
25-32=b
-7=b
Hope it will help you!!!!
Mark me as brainliest!!!!
perimeter of rectangle =2(l+b)
Given=length =32cm
perimeter=50
let breadth =b
perimeter =2(l+b)
50=2(32+b)
50÷2=32+b
25=32+b
25-32=b
-7=b
Hope it will help you!!!!
Mark me as brainliest!!!!
Answered by
1
Step-by-step explanation:
Given that, the perimeter of a rectangle is 50 cm and its length is 32 cm.
Let,
- Breadth of the rectangle = x cm.
Formula used :
Perimeter of the rectangle = 2(l+b)
According to the question,
2(32+x) = 50
→ 32+x = 50/2
→ 32+x = 25
→ x = 25-32
→ x = -7
After calculation, we get x = -7.
But breadth of a rectangle can't be in negative sign. That's why your question is wrong.
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