Question

the perimeter of a rectangle is 50 cm.the length is 5 cm more than its breadth.find the length and breadth of the rectangle.​

Answer 1

GIVEN:

• Perimeter of rectangle = 50 cm
• Length is 5 cm more than its breadth

TO FIND:

• What is the length and breadth of the rectangle ?

SOLUTION:

☞ We have given that the length is 5 cm more than its breadth

According to question:-

$\rm{\dashrightarrow L = B + 5....1)}$

We know that the formula for finding the perimeter of the rectangle is:-

$\bf{\star \: Perimeter = 2(Length + Breadth) \: \star}$

According to question:-

On putting the given values in the formula, we get

$\rm{\dashrightarrow 50 = 2(B + 5 + B)}$

$\rm{\dashrightarrow 50 = 2(2B + 5) }$

$\rm{\dashrightarrow \cancel\dfrac{50}{2} = 2B + 5 }$

$\rm{\dashrightarrow 25 = 2B + 5 }$

$\rm{\dashrightarrow 25-5 = 2B}$

$\rm{\dashrightarrow 20 = 2B}$

$\rm{\dashrightarrow \cancel\dfrac{20}{2} = B}$

$\bf{\star \: 10 \: cm = B \: \star}$

Put the value of 'B' in equation 1)

$\rm{\dashrightarrow L = 10 + 5}$

$\bf{\star \: L = 15 \: cm \: \star}$

❝ Hence, the length and breadth of the rectangle is 15 cm and 10 cm respectively. ❞

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Answer 2

✯✯ QUESTION ✯✯

The perimeter of a rectangle is 50 cm.the length is 5 cm more than its breadth.find the length and breadth of the rectangle...

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Let\:the\:Breadth\:be=x}$

➮As Given that lenth is 5cm more than breadth..So,

$\longmapsto\tt{Length\:of\:Rectangle=x+5}$

$\longmapsto\tt{Perimeter\:of\:Rectangle=50cm}$

➥Using Formula : -

$\longmapsto\tt{\small{\boxed{\bold{\bold{\purple{\sf{Perimeter\:of\:Rectangle=2(l+b)}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{50=2(l+b)}$

$\longmapsto\tt{50=2(x+x+5)}$

$\longmapsto\tt{50=2(2x+5)}$

$\longmapsto\tt{\cancel\dfrac{50}{2}=2x+5}$

$\longmapsto\tt{25=2x+5}$

$\longmapsto\tt{25-5=2x}$

$\longmapsto\tt{20=2x}$

$\longmapsto\tt{x=\cancel\dfrac{20}{2}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{x}\orange{=}\purple{10cm}}}$

➥Now ,

$\longmapsto\tt{Breadth=x}$

$\longmapsto\tt{10cm}$

$\longmapsto\tt{Length=x+5}$

$\longmapsto\tt{10+5}$

tex]\longmapsto\tt{15cm}[/tex]

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➥VERIFICATION : -

$\longmapsto\tt{Perimeter\:of\:Rectangle=2(l+b)}$

$\longmapsto\tt{50=2(15+10)}$

$\longmapsto\tt{50=2(25)}$

$\longmapsto\tt{50=50}$

$\pink\longmapsto\:\large\underline{\boxed{\bf\orange{L.H.S}\red{=}\green{R.H.S}}}$

✺ HENCE VERIFIED ✺