Question

the perimeter of a rectangle is 52 cm and its width =6cn find its length ​

Answer 1

Answer:

Perimeter of rectangle =

$2 \times (l + b) \\ so \: 2 \times (l + b) = 52 \\ 2 \times (l + 6) = 52 \\ l + 6 = \frac{52}{2 } \\ l + 6 = 26 \\ l = 26 - 6 \\ l = 20$