Question

The perimeter of a rectangle is 52 cm and its width is 42/5

cm. Find its length.

Answer 1

Answer:

The equations are:

2 x a +2 x b= 42

a = b+5

replacing a into the first equation we obtain

2(b + 5) + 2 x b= 42

4 x b = 32

b = 8

a = 13

Perimeter

26+16 = 42

Answer 2

Answer:

length = 88/5 cm

Step-by-step explanation:

width = 42/5 cm

length = k

perimeter of rectangle= 52 cm

2(l+b)= 52

2(k+ 42/5)= 52

k+ 42/5=52/2

k + 42/5 = 26

k = 26-42/5

k=( 130-42)/5

= 88/5

length = 88/5 cm