Question

The perimeter of a rectangle is 52 cm, where length is 6 cm more than the width of the rectangle.
Form the pair of linear equations for the above situation and find the dimensions of the rectangle
graphically

Answer 1

Answer:

16

Step-by-step explanation:

perimeter =2×(length +width)

width =x

length=x+6

52=2×(x+x+6)

52=2×(2x+6)

52/2=2x+6

26=2x+6

2x=26_6

2x=20

x=10

width=10

length=10+6=16