the perimeter of a rectangle is 52 CM where length is 6 CM more than the width of the rectangle. form the pair of linear equations for the above situation and find the dimensions of the rectangle graphically.
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let the width of the rectangle =x
let the length =x
perimeter =2(l+b)
52=2(6x+x)
52/2=6x+x
26=7x
x=26/7
let the length =x
perimeter =2(l+b)
52=2(6x+x)
52/2=6x+x
26=7x
x=26/7
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