Question

the perimeter of a rectangle is 52 m. The length is 2 more than twice its width . Find the dimension of the rectangle​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Let the width of the perimeter be X

the length of the perimeter is 2x+2

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perimeter of rectangle = 2(l+b)

52 = 2(2x+2+x)

52 = 4x +4 +2x

52 -4 = 6x

48 = 6x

x = 48/6

x = 8

breadth= x = 8m

length = 2x+2 = 2(8)+2 = 16+2 = 18 m